Question

Возвести в степень
(m^6/n^3)^2
(-3a/2b^2)^4
(-5a^3b^4/3c^5d^7)^3

Answer 1

$( \frac{m^{6} }{n^{3}})^{2} = \frac{ {m}^{12} }{n^{6} }$
$(\frac{ - 3a}{2 {b}^{2} } )^{4} = \frac{( - 3) ^{4}a^{4} }{ {2}^{4} {b}^{8} } = \frac{81 {a}^{4} }{16 {b}^{8} }$
$(\frac{ - 5a ^{3} 3 {b}^{4} }{3 {c}^{5} 5 {d}^{7} } )^{3} = - (\frac{15a ^{3} {b}^{4}}{ 15{c}^{5} {d}^{7} } ) ^{3} = - \frac{ {a}^{9} {b}^{12} }{ {c}^{15} {d}^{21} }$