Question

Решить 5* ................... пожалуйста bitte please

Answer 1

5*.(3. 2/11)*(6-13.2/11)+(13.2/11)*(3,2/11-6)=(3. 2/11)*(6-13.2/11)+(3.2/11+10)*(3,2/11-6)=

=(3. 2/11)*(6-13.2/11)+(3,2/11)*(3,2/11-6)+10*(3,2/11-6)=

=(3,2/11)*(6-13,2/11+3,2/11-6)+10*(3,2/11-6)=

=3,2/11*(-10)+10*(3,2/11-6)=10(-3,2/11+3,2/11-6)=10*(-6)=-60

ответ:-60

=

Answer 2

$3\frac{2}{11}\cdot (6-13\frac{2}{11})+13\frac{2}{11}\cdot (3\frac{2}{11}-6)=\frac{35}{11}\cdot \frac{6\cdot 11-145}{11} +\frac{145}{11}\cdot \frac{35-6\cdot 11}{11}=\\\\=\frac{35}{11}\cdot \frac{-79}{11}+\frac{145}{11}\cdot \frac{-31}{11}=\frac{-2765-4495}{121}=-\frac{7260}{11}=-60$