Question

Разложить на множители квадратный трехчлен :

Answer 1

$\frac{2}{3} x^{2} +2x-12\\\\\frac{2}{3}x^{2} +2x-12=0\\\\\frac{1}{3}x^{2}+x-6=0\\\\x^{2} +3x-18=0\\\\D=3^{2}-4*(-18)=9+72=81=9 ^{2}\\\\x_{1} =\frac{-3+9}{2} =3\\\\x_{2=\frac{-3-9}{2}} =-6\\\\\\\frac{2}{3}x^{2}+2x-12=\frac{2}{3}(x-3)(x+6)$