Question

Помогите решить номер 63 пожалуйста!

Answer 1

$( \frac{16}{ {a}^{2} + 4a + 16} - \frac{2a}{4 - a} - \frac{ {a}^{3} + 20 {a}^{2} }{ {a}^{3} - 64} ) \times (a - 4 + \frac{12a}{a - 4} ) = ( \frac{16}{ {a}^{2} + 4a + 16} + \frac{2a}{a - 4} - \frac{ {a}^{3} + 20 {a}^{2} }{(a - 4)( {a}^{2} + 4a + 16)} \times ( \frac{ {(a - 4)}^{2} }{a - 4} + \frac{12a}{a - 4} ) = \frac{16(a - 4) + 2a( {a}^{2} + 4a + 16) - {a}^{3} - 20 {a}^{2} }{(a - 4)( {a}^{2} + 4a + 16)} \times \frac{ {a}^{2} - 8a + 16 + 12a}{a - 4} = \frac{16a - 64 + 2 {a}^{3} + 8 {a}^{2} + 32a - {a}^{3} - 20 {a}^{2} }{(a - 4)( {a}^{2} + 4a + 16)} \times \frac{ {a}^{2} + 4a + 16}{a - 4} = \frac{ {a}^{3} - 12 {a}^{2} + 48a - 64 }{(a - 4) ^{2} } = \frac{ {(a - 4)}^{3} }{ {(a - 4)}^{2} } = a - 4$