Question

20 баллов
(x²+3x)²+4(x+1.5)²-6 = 0

Answer 1

(x²+3x)²+4(x+1,5)²-6=0

(x²+3x)²+4(x²+3x+2,25)-6=0
x²+3x=t
t²+4(t+2,25)-6=0
t²+4t+9-6=0
t²+4t+3=0
D=16-12=4=2²
t=(-4±2)/2
t1=-3;t2=-1
1)x²+3x+3=0
D=9-12=-3<0
x€∅

2)x²+3x+1=0
D=9-4=5
x=(-3±√5)/2