Question

Помогите решить плиз!

4(5р(х+1)-5р(х+2)),
Если р(х)=4х-5

Answer 1

p(x) = 4x - 5

p(x + 1) = 4*(x + 1) - 5 = 4x + 4 - 5 = 4x - 1

p(x + 2) = 4*(x + 2) - 5 = 4x + 8 - 5 = 4x + 3

4*(5p(x+1) - 5p(x+2)) = 4*5*(p(x+1) - p(x+2)) = 20(4x - 1 - (4x + 3)) = 20(4x - 1 - 4x - 3) = 20*(-4) = -80