Question

помогите решить пожалуйста

Answer 1

$\sin^2 2(\pi+1)+\cos^2 2(\pi-1)=\sin^2 (2\pi+2)+\cos^2 (2\pi-2)=\\ \\ =\sin^2 2+\cos^2 2=1$

Answer 2

$sin^2\, 2(\pi +1)+cos^2\, 2(\pi -1)=sin^2(2\pi +2)+cos^2(2\pi-2)=\\\\=sin^2\, 2+cos^2(-2)=sin^2\, 2+cos^2\, 2=1\\\\\\\star \; \; sin(2\pi +\alpha )=sin\alpha \; \; ,\; \; cos(2\pi +\alpha )=cos\alpha \; \; ,\; \; cos (-\alpha)=cos\alpha \; \; \star$