Question

(log11 88 -1 )(1-log8 88)

Answer 1

$(\log_{11} 88-1)(1-\log_{8}88)=(\log_{11} (11\cdot8)-1)(1-\log_{8}(11\cdot8)) =\\ \\ =(\log_{11} 11+\log_{11}8-1)(1-(\log_{8}11+\log_{8}8))=\\ \\ =(1+\log_{11}8-1)(1-(\log_{8}11+1))=\log_{11}8\cdot(1-\log_{8}11-1)=\\ \\ =\log_{11}8\cdot(-\log_{8}11)=-\log_{11}8\cdot\frac{1}{\log_{11}8}= -1$

Ответ: -1