Question

Найдите корни уровнения

Answer 1

$\frac{5y - 3(y+3)-(2-y)}{y(y+3)} =0\\\\ \frac{5y-3y-9-2+y}{y(y+3)} =0\\\\ \frac{3y-11}{y(y+3)} =0\\\\ y=\frac{11}{3} =3\frac{2}{3}$

Ответ: $3\frac{2}{3}$

2.

$\frac{(2x-7)(x+1)-(x+2)(x-4)-(x+6)}{(x+1)(x-4)} =0\\\\ \frac{2x^2-5x-7-x^2+2x+8-x-6}{(x-1)(x+4)} =0\\\\ \frac{x^2-4x-5}{(x-1)(x+4)} =0\\\\ \frac{(x+1)(x-5)}{(x+1)(x+4)} =0\\\\ x=5;x\neq -1$

Ответ: 5

Answer 2

1)5/(у+3)-3/у=(2-у)/(у²+3у)
(5у-3(у+3))/у(у+3)=(2-у)/у(у+3)
{у(у+3)≠0;у≠0;у≠-3
{5у-3у-9=2-у
2у+у=2+9
3у=11
у=11/3
ответ у=11/3

2)(2х-7)/(х-4)-(х+2)/(х+1)=(х+6)/(х-4)(х+1)
((2х-7)(х+1)-(х-4)(х+2))/(х-4)((х+1)=

(х+6)/(х-4)(х+1)
{(х-4)(х+1)≠0;х=4;х≠-1

{(2х-7)(х+1)-(х-4)(х+2)=х+6
2х²+2х-7х-7-х²-2х+4х+8-х-6=0
х²-4х-5=0
Д=16+20=36=6²
х=(4±6)/2
х1=5;х2=-1

ответ х=5