Question

Деление дробей:

9р^2-1\рg-2g:1-3р\3р-6

Answer 1

$\frac{9 {p}^{2} - 1 }{pg - 2g} \div \frac{1 - 3p}{3p - 6} = \frac{9 {p}^{2} - 1}{pg - 2g} \times \frac{3p - 6}{1 - 3p} = \frac{(3p - 1)(3p + 1)}{g(p - 2)} \times \frac{3(p - 2)}{1 - 3p} = \frac{ - (1 - 3p) \times (3p + 1) \times 3(p - 2)}{g(p - 2) \times (1 - 3p)} = \frac{ - 3(3p + 1)}{g}$