Question

помогите разложить и решить

Answer 1

$(-\frac{6a^{3}x^{2}}{7b^{2}y^{3}})^{3} :(\frac{3a^{4}x^{3}}{14b^{3}y^{5}})^{2} =-\frac{6^{3}a^{9}x^{6}}{7^{3}b^{6}y^{9}} *\frac{14^{2}b^{6}y^{10}}{3^{2}a^{8}x^{6}}=-\frac{3^{3}*2^{3}*a*y*2^{2}*7^{2}}{7^{3}*3^{2}}=-13\frac{5}{7}ay$

Answer 2

$( - \frac{6 {a}^{3} {x}^{2} }{7 {b}^{2} {y}^{3} } ) ^{3} \div {( \frac{3 {a}^{4} {x}^{3} }{14 {b}^{3} {y}^{5} }) }^{2} = - \frac{ {3}^{3} \times {2}^{3} {a}^{9} {x}^{6} }{ {7}^{3} {b}^{6} {y}^{9} } \div \frac{ {3}^{2} {a}^{8} {x}^{6} }{ {7}^{2} \times {2}^{2} {b}^{6} {y}^{10} } = - \frac{ {3}^{3} \times {2}^{3} {a}^{9} {x}^{6} \times {7}^{2} \times {2}^{2} {b}^{6} {y}^{10} }{ {7}^{3} {b}^{6} {y}^{9} \times {3}^{2} {a}^{8} {x}^{6} } = - \frac{3 \times {2}^{5} a y }{7} = - \frac{3 \times 32ay}{7} = - \frac{96ay}{7} = - 13 \frac{5}{7} ay$