Question

$\frac{49}{16}^{x+1} =\frac{4}{7}^{9}$
решите уравнение

Answer 1

${( \frac{49}{16}) }^{x + 1} = {( \frac{4}{7}) }^{9} \\ {( \frac{7}{4}) }^{2(x + 1)} = {( \frac{7}{4} )}^{ - 9} \\ 2( x + 1) = - 9 \\ 2x + 2 = - 9 \\ 2x = - 11 \\ x = - 5.5$