Question

Допоможітть з Математикою

Answer 1

${(0.3)}^{ \frac{ {x}^{2} - x - 12 }{x} } = 1 \\ {(0.3)}^{ \frac{ {x}^{2} - x - 12 }{x} } = {(0.3)}^{0} \\ \frac{ {x}^{2} - x - 12 }{x} = 0 \\ {x}^{2} - x - 12 = 0 \\ d = {b}^{2} - 4ac = 1 - 4 \times 1 \times ( - 12) = 1 + 48 = 49 \\ x1 = \frac{1 + 7}{2} = 4 \\ x2 = \frac{1 - 7}{2} = - 3$
4*(-3) = -12