Question

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₴₴₴₴₴₴₴₴₴₴₴₴₴

Answer 1

3.

$\dfrac{m^2}{m^2-9}-\dfrac{m}{m+3}=\dfrac{m^2}{(m+3)(m-3)}-\dfrac{m}{m+3}=\\\\ \\ =\dfrac{m^2}{(m+3)(m-3)}-\dfrac{m(m-3)}{(m+3)(m-3)}=\\ \\\\ =\dfrac{m^2-m(m-3)}{(m+3)(m-3)}=\dfrac{m^2-m^2+3m}{m^2-9}=\dfrac{3m}{m^2-9}$

4.

$\dfrac{14p^2}{7p+3}-\dfrac{2p}{1}=\dfrac{14p^2}{7p+3}-\dfrac{2p*(7p+3)}{7p+3}=\\ \\ \\ =\dfrac{14p^2-2p(7p+3)}{7p+3}=\dfrac{14p^2-14p^2-6p}{7p+3}=\\ \\ \\ =-\dfrac{6p}{7p+3}$