Question

помогите пожалуйстааа
А36, А37, А39

Answer 1

а36. a = 1 1/2 = 3/2
$(2 \times \frac{3}{2} - 1)^{3} + 6(4 \times \frac{9}{4} - 4 \times \frac{3}{2} + 1) + 3(8 \times \frac{3}{2} - 4) + 8 = {2}^{3} + 6 \times 4 + 3 \times 8 + 8 = 8 + 24 + 2 4 + 8 = 64$

a37. a = 1 1/3 = 4/3
${(3 \times \frac{4}{3} + 2)}^{3} - 9(9 \times \frac{16}{9} + 12 \times \frac{4}{3} + 4) + 3(27 \times \frac{4}{3} + 18) - 27 = {6}^{3} - 9 \times 36 + 3 \times 54 - 27 = 216 - 324 + 162 - 27 = 54 - 27 = 27$
а39. a = sqrt(2)
$(2 \times 2 + 2 \sqrt{2} + 2)(2 \times 2 - 2 \sqrt{2} + 2)(4 - 4) = (6 + 2 \sqrt{2} )(6 - 2 \sqrt{2} ) \times 0 = 0$

Answer 2

Ответ:.....................