Question

вычислить a^2-2ab+b^2-3a+3a a=10/7 b= -11/7

Answer 1

${a}^{2} - 2ab + {b}^{2} - 3a + 3b = {(a - b)}^{2} - 3(a - b) = (a - b)(a - b - 3)$
При а = 10/7, b = -11/7:
$( \frac{10}{7} - ( - \frac{11}{7} )( \frac{10}{7} - ( - \frac{11}{7} ) - 3) = ( \frac{10}{7} + \frac{11}{7} )( \frac{10}{7} + \frac{11}{7} - 3) = \frac{21}{7} ( \frac{21}{7} - 3) = 3 \times (3 - 3) = 3 \times 0 = 0$