Question

(2/(3-x)^2+3/(x^2-9))*(x-3)^2-5x/(x+3)

Answer 1

$(\frac{2}{(x-3)^2} +\frac{3}{(x-3)(x+3)} )\cdot (x-3)^2 - \frac{5x}{x+3} =\\ = \frac{2\cdot (x-3)^2}{(x-3)^2} +\frac{3\cdot (x-3)^2}{(x-3)(x+3)} - \frac{5x}{x+3} = 2+\frac{3\cdot (x-3)}{x+3} - \frac{5x}{x+3} =\\ = 2+\frac{3x-9-5x}{x+3} = 2+\frac{-2x-9}{x+3} = \frac{2x+6-2x-9}{x+3} =-\frac{3}{x+3}$