Question

₼(₼smskskksksk 4.1 sjjajaja

Answer 1

$\frac{a-2}{a^2-2a+4} +\frac{4a+8}{a^3+8} =\frac{a-2}{a^2-2a+4} +\frac{4(a+2)}{(a+2)(a^2-2a+4)}=\frac{a-2+4}{a^2-2a+4} = \\ \\ = \frac{a+2}{a^2-2a+4} \\ \\ OTBET: \ A)$