Question

2х/3-(х-1)/6+(х+2)/2≥0

Answer 1

$\frac{2x}{3}-\frac{x-1}{6}+\frac{x+2}{2}\geq 0\; \Big |\cdot 6\\\\4x-(x-1)+3(x+2)\geq 0\\\\4x-x+1+3x+6\geq 0\\\\6x+7\geq 0\\\\6x\geq -7\\\\x\geq -\frac{7}{6}\\\\x\in [-1\frac{1}{6},+\infty )$