Question

(4sin55°+cos145°)^2+(4cos55°+145°)^2

Answer 1

(4sin55°+cos145°)²+(4cos55°-sin145°)²=

=(4sin55°+cos(90°+55°))²+(4cos55°-sin(90°+55°))²=

=(4sin55°-sin55°)²+(4cos55°-cos55°)²=

=(3sin55°)²+(3cos55°)²=

=9sin²55°+9cos²55°=

=9(sin²55°+cos²55°)=

=9•1=9 (Ответ)