Question

Пж по подробнее заранее спасибо

Answer 1

$\displaystyle \frac{5^{-14}\cdot25^{3n}}{125^{n-4}}=5\\ \\ \frac{5^{-14}\cdot 5^{6n}}{5^{3n-12}}=5\\ \\ 5^{-14+6n-3n+12}=5\\ \\ 5^{3n-2}=5^1\\ 3n-2=1\\ 3n=3\\ n=1$

Answer 2

$\frac{ {5}^{ - 14} \times {25}^{3n} }{ {125}^{n - 4} } = 5 \\ \\ \frac{ {5}^{ - 14} \times {5}^{6n} }{ {5}^{3n - 12} } = 5 \\ \\ {5}^{ - 14 + 6n - (3n - 12)} = {5}^{1} \\ \\ - 14 + 6n - 3n + 12 = 1 \\ \\ 6n - 3n = 1 + 14 - 12 \\ \\ 3n = 3 \\ \\ n = 1$


ОТВЕТ: 1