Question

Решить уравнение:
$8x^{2} - 3(x-4)=12$

Answer 1

8х²-3х+12=12

8х²-3х=12-12

8х²-3х=0

х(8х-3)=0

х=0

или 8х-3=0

8х=3

х=3/8

Answer 2

8x² - 3(x - 4) = 12
8x² - 3x + 12 - 12 = 0
8x² - 3x = 0
8x² - 3x = 0
x(8x - 3) = 0
x = 0
8x - 3 = 0
x = 3/8