Question

Помогите плиз решить 2Б007

Answer 1

$\dfrac{\sqrt[6] {64} \cdot \sqrt[3]{2} }{(\frac{1}{4})^{\frac{2}{3}}\cdot 16x} =2^{\frac{5}{3}}\cdot 32^{-1} \\ \dfrac{2 \cdot \sqrt[3]{2} \cdot 2 \cdot \sqrt[3]{2} }{ 16x} = \dfrac{2^{\frac{5}{3}}}{ 32} \\ \\ \dfrac{2^{\frac{8}{3}} }{ x} = \dfrac{2^{\frac{5}{3}}}{ 2} \\ \\ \frac{2}{ x} = \frac{1}{ 2}$

x = 4

Ответ: 4

Answer 2

$\frac{\sqrt[6]{2^6}*\sqrt[3]{2}}{\sqrt[3]{\frac{1}{16}}*16x} =\sqrt[3]{2^5} *2^{-5}\\ 2\sqrt[3]{2}*2^5 *\sqrt[3]{16}=2\sqrt[3]{4}*16x\\ 2^5\sqrt[3]{8} =2^4x\\ 2*2=x\\ x=4$