Question

ПОМОГИТЕ ПОЖАЛУЙСТА

Answer 1

$1)\\ (x+1)(x+2)-(x-3)(x+4)=6 \\ x^2+2x+x+2-(x^2+4x-3x-12)=6 \\ x^2+2x+x+2-x^2-x+12=6 \\ 2x+14=6 \\ 2x=-8 \\ x=-4 \\ 3) \\ 24-(3y+1)(4y-5)=(11-6y)(2y-7) \\ 24-12y^2+11y+5=22y-77-12y^2+42y \\ 24+11y^2+5=22y-77+42y \\ 29+11y=64y-77 \\ 11y-64y=-77-29 \\ -53y=-106 \\ y=\frac {-106}{-53} \\ y=2$
$4) \\ (6y+2)(5-y)=47-(2y-3)(3y-1) \\ 30y-6y^2+10-2y=47-6y^2+11y-3 \\ 30y+10-2y=47+11y-3 \\ 28y-11y=44-10 \\ 17y=34 \\ y=\frac {34}{17} \\ y=2$