Question

Найдите производные функции y=8 arccos x -3^3+cosx

Answer 1

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Answer 2

$y = 8arccos(x) -3^{3+cosx}\\ y'=-\frac{8}{\sqrt{1-x^2}} +3^{3+cosx}*ln3*sinx$

$y=8arccos(x)-3^3+cosx\\ y'=-\frac{8}{\sqrt{1-x^2}} -sinx$