Question

Решите уравнение
9x^2-160x-36=0

Answer 1

$9x^{2} - 160x - 36 = 0 \\ D/4 = 80^{2} + 9*36 = 6400 + 324 = 6724 \\ \\ x_{1} = \dfrac{80 + 82}{9} = 18 \ ; \ x_{2} = -\dfrac{2}{9}$

Ответ: x₁ = 18, x₂ = -2/9

Answer 2

Находим дискриминант:

D = 160² + 4*9*36 = 25600 + 1296 = 26896

√D = √26896 = 164

x₁ = (160+164)/18 = 18

x₂ = (160 - 164)/18 = -(4/18) = -(2/9)