Question

Помогите пожалуйста))

Answer 1

a) (x^2(0) -2x(0)-8)/(2x^2(0)+5x(0)+2)

x(0)=1

(1-2-8)/(2+5+2)=-9/9=-1

x(0)=∞

(x^2(0) /x^2(0) -2x(x0)/x^2(0) -8/x^2(0) )/ (2x^2(0) /x^2(0) +5x(0)/x^2(0) +2/x^2(0) )

=(1-0-0)/(2+0+0)=1/2

x(0)=-2

(x^2(0) -2x(0)-8)/(2x^2(0)+5x(0)+2)

[ (-2)^2-2*(-2)-8)] / [ 2*(-2)^2+5*(-2)+2 ] =

=[ 4+4-8 ] / [ 8 -10+2] = 0/0=∞