Question

Найти предел !!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Поскольку $(e^{2x}-1)\sim 2x,~~ tg8x\sim 8x$ при $x\to 0$, то

$\displaystyle \lim_{x \to 0} \frac{e^{2x}-1}{tg8x}=\lim_{x \to 0}\frac{2x}{8x}=0.25$