Question

Нужен 5 и 7 номер, помогите.

Answer 1

5)y=5sinx-1/2*x ;xo=-π/3
K=y'(x)
y'(x)=(5sinx-1/2*x)'=5cosx-1/2
y'(xo)=y'(-π/3)=5cos(-π/3)-1/2=
5/2-1/2=4/2=2
K=y'(-π/3)=2
7)y=(x+1)²;y=0;x=1
y=0;(x+1)²=0;x=-1
S=интеграл( -1. до 1)(x+1)²dx=
((х+1)³/3)(-1. до 1)

=8/3-(1-1)³/3==8/3