Question

2sin^2x-sinx-1=0 помогите,срочноо

Answer 1

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Answer 2

sinx=t

2t^2-t-1=0

D=1+8=9

t1=(1+3)/2*2=4/4=1

t2=(1-3)/2*2=-2/4=-1/2

sinx=1

x=p/2 + 2pn

sinx=-1/2

x=-p/6+pn