Question

помогите найти производную функцию
1)f(x)=2x²+4√x -sin5x
2)f(x)=sin2x/4x

Answer 1

1)f(x)=2x²+4√x -sin5x

f'(x)=4x+4*1/2√x -cos5x * 5 = 4x+2/√x - 5cos5x

2)f(x)=sin2x/4x

f'(x)= [ cos2x * 2 *4x- sin2x*4 ] /16x^2 = [ 8xcos2x-4sin2x ] / 16x^2=

=[2xcos2x-sin2x ] /4x^2