Question

Log2x+log8x=8
Решите плиз

Answer 1

$log_{2}(x) + log_{8}(x) = 8 = \\ log_{2}(x) + log_{ {2}^{3} }(x) = 8 = \\ log_{2}(x) + \frac{1}{3} log_{2}(x) = 8 = \\ \frac{4}{3} log_{2}(x) = 8 = \\ log_{2}(x) = \frac{8}{1} \times \frac{3}{4} = 6 = \\ x = {2}^{6} = 64$