Question

Помогите пожалуйста

Answer 1

1)
$= log_{8}( \frac{12}{15} \times 20 ) = log_{8}( \frac{4}{5} \times 20) = log_{8}(16) = log_{ {2}^{3} }( {2}^{4} ) = \frac{4}{3} \times log_{2}(2) = \frac{4}{3} \times 1 = \frac{4}{3}$
2)
${6}^{3x - 1} = {6}^{1 - 2x} \\ 3x - 1 = 1 - 2x \\ 3x + 2x = 1 + 1 \\ 5x = 2 \\ x = \frac{2}{5}$

Answer 2

$log_{8} 12-log_{8}15+log_{8}20=log_{8}\frac{12*20}{15} =log8_{16}=log_{2^{3}}2^{4}=\frac{4}{3} log_{2} 2 =1\frac{1}{3} \\\\\\6^{3x-1} =6^{1-2x}\\\\3x-1=1-2x\\\\3x+2x=1+1\\\\5x=2\\\\x=0,4$