Question

lim x стремится к 3 (х-3)/(x^2-6x+9)

Answer 1

$lim \frac{x - 3}{ {x}^{2} - 6x + 9} = lim \frac{x - 3}{ {(x - 3)}^{2} } = lim \frac{1}{x - 3} = \frac{1}{0} = \infty$