Question

помогите с 42 пожалуйста!

Answer 1

$\sqrt[3]{\sqrt[3]{3\sqrt{3}}+\sqrt[5]{49\sqrt{7}}+\sqrt{19-4\sqrt{21}}} =$

$\sqrt[3]{3^{\frac{1}{3}+\frac{1}{6}}+7^{\frac{2}{5}+\frac{1}{10}}+\sqrt{(2\sqrt{3}-\sqrt{7})^2}} =$

$\sqrt[3]{\sqrt{3}+\sqrt{7}+2\sqrt{3}-\sqrt{7}} =\\ \\ \sqrt[3]{3\sqrt{3}} =3^{\frac{1}{3} +\frac{1}{6} }=\sqrt{3} \\ \\ OTVET:\sqrt{3}\\ \\\\P.S. (2\sqrt{3}-\sqrt{7})>0$