Question

решите пожалуйста....

Answer 1

$1) \lim_{x \to \infty} \frac{2x^3+3x^2-5}{x^3+1} = \lim_{x \to \infty} \frac{2+\frac{3}{x}-\frac{5}{x^3}}{1+\frac{1}{x^3}} =2$

$2) \lim_{x \to 3} \frac{3-x}{(x-3)(x+3)} = \lim_{x \to 3} \frac{-1}{x+3}=-\frac{1}{6}$

Answer 2

б) lim ( 3-x) / ( 3 -x)( -3 -x) = lim 1 / ( -x -3 ) = -1/6
a) lim (2 + 3/x - 5/ x^3) / ( 1 + 1/x^3) = 2/1 =2