Question

помогите пожалуйста срочно нужно

Answer 1

log₅(150)-log₅(3)+log₅(1/2)-log₅(1)=

=log₅((150*1/2)/3)-0=

=log₅(50*1/2=

=log₅(25)=

=log₅(5²)=

=2

Answer 2

log(5) 6+log(5)25 -log(5)3 +log(5)2^(-1) -log(5)1 =

=log(5)3+log(5)2 +log(5)5^2-log(5)3 -log(5)2-0 = 2log(5)5 =2