Question

12x + 12
2x^2 - 6x
X^2 + 3x^ - 10
9x^2 - 25

Answer 1

1) x=-12/12

x=-1

2) x(2x-6)=0; x=0 или x=3

3) D=7^2; x1,2=(-3+-7)/2= -5; -2

4) x= +-5/3

Answer 2

$12x + 12 = 12(x + 1) \\ 2 {x}^{2} - 6x = 2x(x - 3) \\ {x}^{2} + 3 {x}^{ - 10} = {x}^{2} + 3 \times \frac{1}{ {x}^{10} } = {x}^{2} + \frac{3}{ {x}^{10} } = \frac{ {x}^{12} + 3 }{ {x}^{10} } \\ 9 {x}^{2} - 25 = {3}^{2} {x}^{2} - {5}^{2} = (3x - 5)(3x + 5)$