Question

Задача 2! Срочно!!! Помогите!!!!!!!

Answer 1

$\sqrt[3]{9^{2log_96}-7^{log_79}} = \sqrt[3]{9^{log_96^2}-7^{log_79}} =\\\\ = \sqrt[3]{6^2-9} = \sqrt[3]{27} =3$


$\sqrt[4]{6^{2log_65}-5^{log_59}} = \sqrt[4]{6^{log_65^2}-5^{log_59}} =\\\\= \sqrt[4]{5^2-9} = \sqrt[4]{16} =2$