Предмет: Алгебра, автор: egordavydov68

выразите t через s,l и v: s=2l+ 3/2v (st/l +3t)

MizoriesKun: этот множитель в знаменателе (st/l +3t) ? или это так выглядит (3/2v)* (st/l +3t)

MizoriesKun: аууу

egordavydov68: Секунду

egordavydov68: Там 3/2 * v

egordavydov68: (3/2 *v) ( st/l +3t)

Ответы

Автор ответа: MizoriesKun

s=2l+ (3/2v) *(st/l +3t)

(s-2l): (3/2v) = (st/l +3t)

(s-2l): (3/2v) = (st+3tl) /l

(s-2l): (3/2v) *l= t (s+3l)

t=( (s-2l): (3/2v) *l) / (s+3l)

t=( (s-2l)*2vl / 3*(s+3 l)

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