Question

Указать область определения функции

Answer 1

$y=lg(3x^2-8x-3) \\ \\ ODZ:3x^2-8x-3\ \textgreater \ 0 \\ \\ D=64+36=100 \\ \\ x_{1} =(8+10)/6=3 \\ \\ x_{2} =(8-10)/6=-1/3 \\ \\ +++(-1/3)---(3)+++ \\ \\ x\in(-oo;-1/3)U(3;+oo)$