Question

Помогите решить уравнение пожалуйста

x^2+8x=9

x^2=5x-6

Answer 1

1) x^2 +8x - 9 = 0 
D = 64 - 4*1*(-9) = 64+36 = 100 = 10^2
x1 = (-8+10)/(2*1) = 1
x2 = (-8-10)/(2*1) = -9
2) x^2 - 5x + 6 = 0
D = 25-4*1*6 = 25-24=1
x1 = (5-1)/ 2 = 2
x2 = 6/2 = 3

Answer 2

$1) x^2 +8x - 9 = 0$
$D = 64 - 4*1*(-9) = 64+36 = 100 = 10^2$
$x_{1} = \frac{-8+10}{2*1}= 1$
$x_{2} = \frac{-8-10}{2*1}= -9$

Ответ: -9; 1


$2) x^2 - 5x + 6 = 0$
$D = 25-4*1*6 = 25-24=1$
$x_{1} = \frac{5-1}{ 2*1} = 2$
$x_{2} = \frac{5+1}{ 2*1} = 3$


Ответ: 2; 3.