Question

Помогите перевести на Си

program array18;

var
A: array[1..10] of integer;
i, K: integer;

begin
for i := 1 to 10 do
read(A[i]);
for i := 1 to 9 do
if A[i] > A[10] then
begin
K := i;
break;
end;

writeln(A[K]);
end.

Answer 1

#include <stdio.h>

int main(void)
{
    int arr[10], k;
    for (int i = 0; i < 10; ++i) scanf("%d", &arr[i]);
    for (int i = 0; i < 9; ++i) 
        if (arr[i] > arr[9]) { k = i; break; }
    printf("%d", arr[k]);
}

Answer 2

#include <stdio.h>

int main() {
 int A[10];
 int K = 0;
 for (int i = 0; i < 10; i++)
  scanf("%d", &A[i]);
 for (int i = 0; i < 9; i++)
  if (A[i] > A[9]) {
    K = i;
    break;
  }
printf("%d", A[K]);
}