Question

Помогите решить этот номер пожалуйста!

Answer 1

1) 64/(44-36)(44+36)= 64/8*80= 8/80= 1/10= 0,1
2) (35-25)(35+25)/(17-13)(17+13)= 10*60/4*30= 10*2/4= 5 
3) (101-49)(101+49)/(38-12)(38+12)= 52*150/26*50= 2*3= 6
4) (16,5-43,5)(16,5+43,5)/(2,1-0,6)(2,1+0,6)= -27*60/1,5*2,7= -400

Answer 2

$\displaystyle \frac{64}{44^{2}-36^{2}}= \frac{64}{(44-36)(44+36)}= \frac{64}{8*80}= \frac{64}{640}=0,1 \\ \\ \\ \frac{35^{2}-25^{2}}{17^{2}-13^{2}}= \frac{(35-25)(35+25)}{(17-13)(17+13)}= \frac{10*60}{4*30}= \frac{600}{120}=5 \\ \\ \\ \frac{101^{2}-49^{2}}{38^{2}-12^{2}}= \frac{(101-49)(101+49)}{(38-12)(38+12)}= \frac{52*150}{26*50}=2*3=6 \\ \\ \\ \frac{16,5^{2}-43,5^{2}}{2,1^{2}-0,6^{2}}= \frac{(16,5-43,5)(16,5+43,5)}{(2,1-0,6)(2,1+0,6)}= \frac{-27*60}{1,5*2,7}=-400$