Question

найти производную функции y=cos (π\6 3x)

Answer 1

$1)\; \; y=cos( \frac{\pi }{6}-3x)\\\\y'=-sin(\frac{\pi }{6}-3x)\cdot (-3)= 3\cdot cos(\frac{\pi }{6}-3x)\\\\\\2)\; \; y=cos(\frac{\pi }{6}+3x)\\\\y'=-sin(\frac{\pi }{6}+3x)\cdot 3=-3\cdot sin( \frac{\pi }{6}+3x)$