Question

Помогите пожалуйста решить !!

Answer 1

$\frac{2b \sqrt{b} - 2 {b}^{ - \frac{1}{2} } }{ {b}^{ - 1} - b} = \frac{2b \times {b}^{ \frac{1}{2} } - \frac{2}{ {b}^{ \frac{1}{2} } } }{ \frac{1}{b} - b } = \frac{2 {b}^{ \frac{3}{2} } - \frac{2}{ {b}^{ \frac{1}{2} } } }{ \frac{1 - {b}^{2} }{b} } = \frac{ \frac{2 {b}^{ \frac{4}{2} } - 2}{ {b}^{ \frac{1}{2} } } }{{ \frac{1 - {b}^{2} }{b} } } = \frac{ \frac{2 {b}^{2} - 2 }{ {b}^{ \frac{1}{2} } } }{ \frac{1 - {b}^{2} }{b } } = \frac{2b( {b}^{2} - 1)}{ {b}^{ \frac{1}{2} } (1 - {b}^{2}) } = - 2 {b}^{ \frac{1}{2} } = - 2 \sqrt{b}$

Answer 2

(2*b*√b-2*b⁻¹/²)/(b⁻¹-b)=(2*b*√b-(2/√b))/((1/b)-b)=2*(b*√b-(1/√b))/2/((1/b)-b)=
=(2*(b²-1)/√b)/((1-b²)/b)=-(2*(b²-1)/√b)/((b²-1)/b)=-2*(b²-1)*b/((b²-1)*√b)=-2*√b.