Question

Вычеслить $f'(\frac{\pi}{8})$ , если $f(X)=sin^{2} 2x$

Answer 1

f'(x) = 2sin2x*cos2x*2 = 2sin4x
f'(pi/8) = 2sin(4*pi/8) = 2sin(pi^2) = 2*1=2