Question

УПРОСТИТЕ ТРИГОНОМЕТРИЧЕСКОЕ ВЫРАЖЕНИЕ

Answer 1

$(cos^2x+sin^2x-cos^2x+sin^2x) \frac{cosx}{sinx} =2sin^2x \frac{cosx}{sinx}=2cosxsinx= \\ =sin(2x)$
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$tg^2x(cos^2x+sin^2x+cos^2x-sin^2x)^2=tg^2x*(2cos^2x)^2=sin^2(2x)$