Question

Прошу, помогите найти производную
f(z) = 1/49 (z^3-1)^3; f'(2)

Answer 1

f '(z)= 1/49 * 3*(z^3-1)^2 *(z^3-1)' = 1/49 * 3*(z^3-1)^2 * 3z^2 = 
=9z^2/49  *(z^3-1)^2

f '(2) = 9*4/49  *(8-1)^2= 36/49 * 49 = 36