Question

(6,62^2+5,4×3,38+1,22×3,38)/(20,1^2-13^2+33,1×12,9
$\frac{6,62^2+5,4×3,38+1,22×3,38}{20,1^2-13^2+33,1×12,9}$
помогите решать этот задание до завтра

Answer 1

$=\frac{6.62^2+3.38(5.4+1.22)}{(20.1-13)(20.1+13)+33.1*12.9} = \\ \\ \frac{6.62^2+3.38*6.62}{7.1*33.1+33.1*12.9} =\frac{6.62(6.62+3.38)}{33.1(7.1+12.9)} =\frac{6.62*10}{33.1*20} = \frac{6.62}{66.2} =0.1$